If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2-5x+3=7
We move all terms to the left:
6x^2-5x+3-(7)=0
We add all the numbers together, and all the variables
6x^2-5x-4=0
a = 6; b = -5; c = -4;
Δ = b2-4ac
Δ = -52-4·6·(-4)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-11}{2*6}=\frac{-6}{12} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+11}{2*6}=\frac{16}{12} =1+1/3 $
| -2(t-15)=18 | | a+3a=2a-7 | | 5−4+7x+1=x+7 | | 180=48+x+44 | | 4=k-3/4 | | 600=2(70+w)+2 | | 5x-{x+3}=1/3{9x+18}-5 | | 0.80x+0.05(160)=0.40(48) | | 5−4+7x+1=3x+7 | | 180=48+x-44 | | 4.6-(-b)=-9 | | b-9+3b=14 | | 2y^2-5y-84=0 | | 4w-20=-4 | | t/2.9=4.5 | | 5−4+7x+1=8x+7 | | 180=48+(x-44) | | 1/2(2x+4)=3x-4 | | 2(-9w-12)=12 | | 13x-x=144 | | 58=-2(4x+5)-6(4x-6) | | 2(2m+3)=m+9 | | -5(y-7)=-7y+15 | | 8x−13+7x−17=180 | | 4/5g+2=6 | | 4d+14=3d | | F-6=f*8 | | x*0.625=1 | | -130.5-9b=-55.104=3.2 | | 1/3x-7=-15 | | 64=3.14r^2(10) | | -8u+6(u+3)=14 |